Surface area
Adapted from Wikipedia Β· Adventurer experience
The surface area (symbol A) of a solid object is a way to measure how much space the outside of that object covers. Imagine wrapping something in paper; the amount of paper needed would be close to the object's surface area. For simple shapes with flat sides, like a box, the surface area is just the total area of all the flat parts added together.
For round or curved shapes, such as a sphere, finding the surface area is more complicated. It uses special math called infinitesimal calculus, which helps break the curved surface into very small, flat pieces that are easier to measure.
A long time ago, smart people like Henri Lebesgue and Hermann Minkowski worked on a general way to find the surface area of any shape, even very strange or irregular ones. Their ideas helped create a field of math called geometric measure theory, which looks at how to measure surfaces in many different situations.
Definition
Finding the exact size of a surface can be hard, especially when the surface is curved. For simple flat shapes, we can easily measure their area. For curved surfaces like a sphere, we need more advanced math.
One key idea is that the total area of a surface should be the sum of the areas of its parts. This works well for smooth surfaces. For very rough surfaces, it might not be possible to define a clear area.
Common formulas
See also: List of formulas in elementary geometry
Ratio of surface areas of a sphere and cylinder of the same radius and height
Here are some easy formulas to help us learn about the surface area of common shapes. For example, we can compare the surface area of a sphere and a cylinder that are the same size.
The surface area of a sphere is four times pi times the radius squared. For a cylinder, itβs two times pi times the radius times the height plus the radius. When the height of the cylinder is the same as the diameter of the sphere, their surface areas are in a ratio of 2 to 3. This cool fact was found by Archimedes.
| Shape | Formula/Equation | Variables |
|---|---|---|
| Cube | 6 a 2 {\displaystyle 6a^{2}} | a = side length |
| Cuboid | 2 ( l b + l h + b h ) {\displaystyle 2\left(lb+lh+bh\right)} | l = length b = breadth h = height |
| Triangular prism | b h + l ( p + q + r ) {\displaystyle bh+l\left(p+q+r\right)} | b = base length of triangle, h = height of triangle, l = distance between triangular bases, p, q, r = sides of triangle |
| All prisms | 2 B + P h {\displaystyle 2B+Ph} | B = the area of one base P = the perimeter of one base h = height |
| Sphere | 4 Ο r 2 = Ο d 2 {\displaystyle 4\pi r^{2}=\pi d^{2}} | r = radius of sphere d = diameter |
| Hemisphere | 3 Ο r 2 {\displaystyle 3\pi r^{2}} | r = radius of the hemisphere |
| Hemispherical shell | Ο ( 3 R 2 + r 2 ) {\displaystyle \pi \left(3R^{2}+r^{2}\right)} | R = external radius of hemisphere r = internal radius of hemisphere |
| Spherical lune | 2 r 2 ΞΈ {\displaystyle 2r^{2}\theta } | r = radius of sphere ΞΈ = dihedral angle |
| Torus | ( 2 Ο r ) ( 2 Ο R ) = 4 Ο 2 R r {\displaystyle \left(2\pi r\right)\left(2\pi R\right)=4\pi ^{2}Rr} | r = minor radius (radius of the tube) R = major radius (distance from center of tube to center of torus) |
| Closed cylinder | 2 Ο r 2 + 2 Ο r h = 2 Ο r ( r + h ) {\displaystyle 2\pi r^{2}+2\pi rh=2\pi r\left(r+h\right)} | r = radius of the circular base h = height of the cylinder |
| Cylindrical annulus | 2 Ο R h + 2 Ο r h + 2 ( Ο R 2 β Ο r 2 ) = 2 Ο ( R + r ) ( R β r + h ) {\displaystyle {\begin{aligned}&2\pi Rh+2\pi rh+2\left(\pi R^{2}-\pi r^{2}\right)\\&=2\pi \left(R+r\right)\left(R-r+h\right)\end{aligned}}} | R = External radius r = Internal radius h = height |
| Capsule | 2 Ο r ( 2 r + h ) {\displaystyle 2\pi r(2r+h)} | r = radius of the hemispheres and cylinder h = height of the cylinder |
| Curved surface area of a cone | Ο r r 2 + h 2 = Ο r s {\displaystyle \pi r{\sqrt {r^{2}+h^{2}}}=\pi rs} | s = r 2 + h 2 {\displaystyle s={\sqrt {r^{2}+h^{2}}}} s = slant height of the cone r = radius of the circular base h = height of the cone |
| Full surface area of a cone | Ο r ( r + r 2 + h 2 ) = Ο r ( r + s ) {\displaystyle \pi r\left(r+{\sqrt {r^{2}+h^{2}}}\right)=\pi r\left(r+s\right)} | s = slant height of the cone r = radius of the circular base h = height of the cone |
| Regular Pyramid | B + P s 2 {\displaystyle B+{\frac {Ps}{2}}} | B = area of base P = perimeter of base s = slant height |
| Square pyramid | b 2 + 2 b s = b 2 + 2 b ( b 2 ) 2 + h 2 {\displaystyle b^{2}+2bs=b^{2}+2b{\sqrt {\left({\frac {b}{2}}\right)^{2}+h^{2}}}} | b = base length s = slant height h = vertical height |
| Rectangular pyramid | l b + l ( b 2 ) 2 + h 2 + b ( l 2 ) 2 + h 2 {\displaystyle lb+l{\sqrt {\left({\frac {b}{2}}\right)^{2}+h^{2}}}+b{\sqrt {\left({\frac {l}{2}}\right)^{2}+h^{2}}}} | l = length b = breadth h = height |
| Tetrahedron | 3 a 2 {\displaystyle {\sqrt {3}}a^{2}} | a = side length |
| Surface of revolution | 2 Ο β« a b f ( x ) 1 + ( f β² ( x ) ) 2 d x {\displaystyle 2\pi \int _{a}^{b}{f(x){\sqrt {1+(f'(x))^{2}}}dx}} | |
| Parametric surface | β¬ D | r β u Γ r β v | d A {\displaystyle \iint _{D}\left\vert {\vec {r}}_{u}\times {\vec {r}}_{v}\right\vert dA} | r β {\displaystyle {\vec {r}}} = parametric vector equation of surface r β u {\displaystyle {\vec {r}}_{u}} = partial derivative of r β {\displaystyle {\vec {r}}} with respect to u {\displaystyle u} r β v {\displaystyle {\vec {r}}_{v}} = partial derivative of r β {\displaystyle {\vec {r}}} with respect to v {\displaystyle v} D {\displaystyle D} = shadow region |
In chemistry
Surface area helps decide how fast chemicals react. When you make the surface area bigger, the reaction usually happens faster. For example, iron that is ground into a fine powder can catch fire easily, but the same iron in big solid pieces stays safe and can be used in buildings. Sometimes we want a lot of surface area, and other times we want just a little.
See also: Accessible surface area
In biology
The surface area of living things is important for how they stay healthy. For example, animals use their teeth to break food into smaller pieces. This helps their bodies get nutrients better. The lining of the digestive system has tiny parts called microvilli that give more space for absorbing nutrients. Elephants have big ears that help them stay cool.
Cells need the right balance of surface area to volume. As cells get bigger, their volume grows faster than their surface area. This makes it harder for materials to move in and out of the cell. For example, a tiny cell has a surface area to volume ratio that lets materials move easily, but a larger cell has a smaller ratio, so materials move more slowly.
Related articles
This article is a child-friendly adaptation of the Wikipedia article on Surface area, available under CC BY-SA 4.0.
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